| 
 | 
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Let the point of intersection of 
 and 
 be 
, where 
 and 
 are the Brocard
Points, and similarly define 
 and 
.  
 is the first Brocard triangle, and is inversely similar to
.  It is inscribed in the Brocard Circle drawn with 
 as the Diameter.  The triangles 
, 
,
and 
 are Isosceles Triangles with base angles 
, where 
 is the
Brocard Angle.  The sum of the areas of the Isosceles Triangles is 
, the Area of Triangle
.  The first Brocard triangle is in perspective with the given Triangle, with 
, 
, and 
Concurrent.  The Median Point of the first Brocard triangle is the Median Point 
 of the original
triangle.  The Brocard triangles are in perspective at 
.
Let 
, 
, and 
 and 
, 
, and 
 be the Circles intersecting  in the Brocard
Points 
 and 
, respectively.  Let the two circles 
 and 
 tangent at 
 to 
 and 
,
and passing respectively through 
 and 
, meet again at 
.  The triangle 
 is the second Brocard triangle.
Each Vertex of the second Brocard triangle lies on the second Brocard Circle.  
The two Brocard triangles are in perspective at 
.
See also Steiner Points, Tarry Point
References
Johnson, R. A.  Modern Geometry: An Elementary Treatise on the Geometry of the Triangle and the Circle.  Boston, MA:
  Houghton Mifflin, pp. 277-281, 1929.